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When serving a website, delete the unzipped directory if the index file is not found.

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This is a quick solution to rebuild directory structures with missing files. This whole area of the code needs some reworking, as serving the site from a temporary folder is not a robust long term solution.
This commit is contained in:
CalDescent
2021-07-10 15:51:46 +01:00
parent f938d8c878
commit 5a95c827b4
2 changed files with 18 additions and 1 deletions
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14
src/main/java/org/qortal/api/resource/WebsiteResource.java
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@@ -20,6 +20,7 @@ import io.swagger.v3.oas.annotations.media.Schema;
import io.swagger.v3.oas.annotations.parameters.RequestBody;
import io.swagger.v3.oas.annotations.responses.ApiResponse;
import io.swagger.v3.oas.annotations.tags.Tag;
import org.apache.commons.io.FileUtils;
import org.apache.logging.log4j.LogManager;
import org.apache.logging.log4j.Logger;
import org.qortal.api.ApiError;
@@ -355,8 +356,19 @@ public class WebsiteResource {
inputStream.close();
}
return response;
} catch (FileNotFoundException e) {
LOGGER.info("File not found at path: {}", unzippedPath);
if (inPath.equals("/")) {
// Delete the unzipped folder if no index file was found
try {
FileUtils.deleteDirectory(new File(unzippedPath));
} catch (IOException ioException) {
LOGGER.info("Unable to delete directory: {}", unzippedPath, e);
}
}
} catch (IOException e) {
LOGGER.info("Unable to serve file at path: {}", inPath);
LOGGER.info("Unable to serve file at path: {}", inPath, e);
}
return this.get404Response();